Anthony Pascasio

Male, Age 23 Danbury, Connecticut

Anthony Pascasio is a 23 years old male, born on Wednesday, 17th of February 1999. He will turn 24 on February 17, 2025. Our records show he currently resides at 7 Meadowbrook Road, Danbury, 06811-5014 and is affiliated with the No known party affiliation. Anthony is registered to vote in Connecticut since March 7, 2019.

Overview of Anthony Pascasio

Age: 23

Gender: male

Birth year: 1999

Lives in: Danbury

Anthony Pascasio's Voting Profile

Registered to vote since: March 7, 2019

Party Affiliation: No known party affiliation

Status: A

Precinct: 09

District: 002

Polling place: Pembroke School Gym

Voter ID: 005022040

Congressional District: 005

House District: 109

Senate District: 024

Anthony Pascasio Adress & Maps

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Thomas Gerard Adams

Neighbors for Anthony Pascasio

2 Meadowbrook Road, Danbury, 06811-5039
No known party affiliation
3 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
4 Meadowbrook Road, Danbury, 06811-5039
No known party affiliation
5 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
5 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
5 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
5 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
7 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
7 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
7 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
8 Meadowbrook Road, Danbury, 06811-5039
No known party affiliation
8 Meadowbrook Road, Danbury, 06811-5039
No known party affiliation
8 Meadowbrook Road, Danbury, 06811-5039
No known party affiliation
9 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation
9 Meadowbrook Road, Danbury, 06811-5014
No known party affiliation

Income

Salary: $37,070

Net Worth: $1,110,591

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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