Alvaro Rodriguez

Male, Age 35 Danbury, Connecticut

Alvaro Rodriguez is a 35 years old male, born on Wednesday, 19th of August 1987. He will turn 36 on August 19, 2025. Our records show he currently resides at 16 Scuppo Road E2, Danbury, 06811-5253 and is affiliated with the No known party affiliation. Alvaro is registered to vote in Connecticut since August 27, 2018.

Overview of Alvaro Rodriguez

Age: 35

Gender: male

Birth year: 1987

Lives in: Danbury

Alvaro Rodriguez's Voting Profile

Registered to vote since: August 27, 2018

Party Affiliation: No known party affiliation

Status: A

Precinct: 38

District: 007

Polling place: Westside Middle School Academy

Voter ID: 004937636

Congressional District: 005

House District: 138

Senate District: 024

Alvaro Rodriguez Adress & Maps

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Thomas Gerard Adams

Neighbors for Alvaro Rodriguez

15 Scuppo Road 1503, Danbury, 06811-5303
No known party affiliation
15 Scuppo Road 801, Danbury, 06811-5303
No known party affiliation
15 Scuppo Road 1403, Danbury, 06811-5303
No known party affiliation
15 Scuppo Road 601, Danbury, 06811-0000
No known party affiliation
15 Scuppo Road 401, Danbury, 06811-5303
No known party affiliation
15 Scuppo Road 1106, Danbury, 06811-5303
No known party affiliation
15 Scuppo Road 1105, Danbury, 06811-5303
No known party affiliation
16 Scuppo Road D3, Danbury, 06811-5253
No known party affiliation
16 Scuppo Road E4, Danbury, 06811-5253
No known party affiliation
16 Scuppo Road F5, Danbury, 06811-0000
No known party affiliation
16 Scuppo Road D2, Danbury, 06811-5253
No known party affiliation
16 Scuppo Road D 4, Danbury, 06811-5253
No known party affiliation
16 Scuppo Road E3, Danbury, 06811-5253
No known party affiliation
16 Scuppo Road D1, Danbury, 06811-5253
No known party affiliation
16 Scuppo Road F9, Danbury, 06811-5253
No known party affiliation

Income

Salary: $11,165

Net Worth: $859,989

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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