Jason Almodovar

Male, Age 36 Waterbury , Connecticut

Jason Almodovar is a 36 years old male, born on Thursday, 5th of June 1986. He will turn 37 on June 05, 2025. Our records show he currently resides at 22 Seymour Street 1, Waterbury , 06708-3706 and is not affiliated with any political party. Jason is registered to vote in Connecticut since May 23, 2018.

Overview of Jason Almodovar

Age: 36

Gender: male

Birth year: 1986

Lives in: Waterbury

Jason Almodovar's Voting Profile

Registered to vote since: May 23, 2018

Party Affiliation: No known party affiliation

Status: I

Precinct: 03

District: 071

Polling place: Tinker School

Voter ID: 004905189

Congressional District: 003

House District: 071

Senate District: 015

Jason Almodovar Adress & Maps

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Thomas Gerard Adams

Neighbors for Jason Almodovar

17 Seymour Street, Waterbury , 06708-3705
No known party affiliation
17 Seymour Street, Waterbury , 06708-3705
No known party affiliation
18 Seymour Street A, Waterbury , 06708-3706
No known party affiliation
19 Seymour Street, Waterbury , 06708-3705
No known party affiliation
19 Seymour Street 2, Waterbury , 06708-3705
No known party affiliation
19 Seymour Street 3, Waterbury , 06708-3705
No known party affiliation
20 Seymour Street 2, Waterbury , 06708-3706
No known party affiliation
22 Seymour Street 1, Waterbury , 06708-3706
No known party affiliation
22 Seymour Street 3, Waterbury , 06708-5709
No known party affiliation
24 Seymour Street 2, Waterbury , 06708-3706
No known party affiliation
25 Seymour Street, Waterbury , 06708-3705
No known party affiliation
26 Seymour Street 2, Waterbury , 06708-3706
No known party affiliation
26 Seymour Street 1, Waterbury , 06708-3706
No known party affiliation
52 Seymour Street, Waterbury , 06708-3730
No known party affiliation
52 Seymour Street, Waterbury , 06708-3730
No known party affiliation

Income

Salary: $48,418

Net Worth: $1,409,765

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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