Hong Van Tran

Male, Age 70 Danbury, Connecticut

Hong Van Tran is a 70 years old male, born on Friday, 15th of February 1952. He will turn 71 on February 15, 2025. Our records show he currently resides at 5 Jeanette Street, Danbury, 06811-3743 and is affiliated with the No known party affiliation. Hong is registered to vote in Connecticut since July 3, 2017.

Overview of Hong Van Tran

Age: 70

Gender: male

Birth year: 1952

Lives in: Danbury

Phone number: 203-205-5681

Hong Van Tran's Voting Profile

Registered to vote since: July 3, 2017

Party Affiliation: No known party affiliation

Status: A

Precinct: 08

District: 002

Polling place: Pembroke School Gym

Voter ID: 004830726

Congressional District: 005

House District: 108

Senate District: 024

Hong Van Tran Adress & Maps

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Thomas Gerard Adams

Neighbors for Hong Van Tran

1 Jeanette Street, Danbury, 06811-0000
No known party affiliation
2 Jeanette Street, Danbury, 06811-3744
No known party affiliation
2 Jeanette Street 46, Danbury, 06811-3744
No known party affiliation
2 Jeanette Street, Danbury, 06811-3744
No known party affiliation
2 Jeanette Street 70, Danbury, 06811-3744
No known party affiliation
2 Jeanette Street 30, Danbury, 06811-3744
No known party affiliation
2 Jeanette Street, Danbury, 06811-3744
No known party affiliation
5 Jeanette Street, Danbury, 06811-3746
No known party affiliation
5 Jeanette Street, Danbury, 06811-3743
No known party affiliation
5 Jeanette Street, Danbury, 06811-3746
No known party affiliation
6 Jeanette Street, Danbury, 06811-3744
No known party affiliation
6 Jeanette Street, Danbury, 06811-3744
No known party affiliation
6 Jeanette Street, Danbury, 06811-3744
No known party affiliation
6 Jeanette Street, Danbury, 06811-3744
No known party affiliation
6 Jeanette Street, Danbury, 06811-3744
No known party affiliation

Income

Salary: $94,383

Net Worth: $1,180,005

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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