Paola Rivera

Female, Age 23 Bridgeport, Connecticut

Paola Rivera is a 23 years old female, born on Wednesday, 13th of January 1999. She will turn 24 on January 13, 2024. Our records show she currently resides at 1915 Park Avenue, Bridgeport, 06604-1922 and is not affiliated with any political party. Paola is registered to vote in Connecticut since April 17, 2017.

Overview of Paola Rivera

Age: 23

Gender: female

Birth year: 1999

Lives in: Bridgeport

Paola Rivera's Voting Profile

Registered to vote since: April 17, 2017

Party Affiliation: No known party affiliation

Status: A

Precinct: 02

District: 129

Polling place: Central High School

Voter ID: 004813557

Congressional District: 004

House District: 129

Senate District: 022

Paola Rivera Adress & Maps

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Thomas Gerard Adams

Neighbors for Paola Rivera

1884 Park Avenue, Bridgeport, 06604-2229
No known party affiliation
1884 Park Avenue, Bridgeport, 06604-2229
No known party affiliation
1884 Park Avenue, Bridgeport, 06604-2229
No known party affiliation
1907 Park Avenue, Bridgeport, 06604-1922
No known party affiliation
1907 Park Avenue, Bridgeport, 06604-1922
No known party affiliation
1910 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1910 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1915 Park Avenue, Bridgeport, 06604-1922
No known party affiliation
1920 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1920 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1920 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1950 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1950 Park Avenue, Bridgeport, 06604-1923
No known party affiliation
1955 Park Avenue, Bridgeport, 06604-1924
No known party affiliation
1955 Park Avenue, Bridgeport, 06604-1924
No known party affiliation

Income

Salary: $84,724

Net Worth: $981,044

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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