Jennifer L Sanford

Female, Age 51 Danbury, Connecticut

Jennifer L Sanford is a 51 years old female, born on Saturday, 1st of April 1972. She will turn 52 on April 01, 2024. Our records show she currently resides at 2 Bayview Drive, Danbury, Ct 06811-3331 and is affiliated with the No known party affiliation. Jennifer is registered to vote in Connecticut since February 27, 2017. Our records show David I Sanford (72) and Joyce Sanford (72) as possible relatives.

Overview of Jennifer L Sanford

Age: 51

Gender: female

Birth year: 1973

Lives in: Danbury

Jennifer L Sanford's Voting Profile

Registered to vote since: February 27, 2017

Party Affiliation: No known party affiliation

Status: A

Precinct: 09

District: 003

Polling place: Stadley Rough School

Voter ID: 004803998

Congressional District: 005

House District: 109

Senate District: 024

Jennifer L Sanford Adress & Maps

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Thomas Gerard Adams

Neighbors for Jennifer L Sanford

3 Bayview Drive, Danbury, Ct 06811-3330
No known party affiliation
3 Bayview Drive, Danbury, Ct 06811-3330
No known party affiliation
4 Bayview Drive, Danbury, Ct 06811-3331
No known party affiliation
4 Bayview Drive, Danbury, Ct 06811-3331
No known party affiliation
5 Bayview Drive, Danbury, Ct 06811-3330
No known party affiliation
5 Bayview Drive, Danbury, Ct 06811-3330
No known party affiliation
6 Bayview Drive, Danbury, Ct 06811-3331
No known party affiliation
6 Bayview Drive, Danbury, Ct 06811-3331
No known party affiliation
10 Bayview Drive, Danbury, Ct 06811-3331
No known party affiliation
10 Bayview Drive, Danbury, Ct 06811-3331
No known party affiliation

Related Persons

Jennifer L Sanford's parents, siblings, grandparents, aunts, uncles, cousins, and other extended family members.

Danbury, Ct
Born on: Wednesday, 28th of February 1951
Gender: Male
Danbury, Ct
Born on: Thursday, 21st of June 1951
Gender: Female

Income

Salary: $24,158

Net Worth: $879,735

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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