Juan Antonio Fuqua

Male, Age 42 Danbury, Connecticut

Juan Antonio Fuqua is a 42 years old male, born on Thursday, 28th of February 1980. He will turn 43 on February 28, 2024. Our records show he currently resides at 2 Nicholas Street, Danbury, 06810-7109 and is not affiliated with any political party. Juan is registered to vote in Connecticut since October 24, 2016.

Overview of Juan Antonio Fuqua

Age: 42

Gender: male

Birth year: 1980

Lives in: Danbury

Juan Antonio Fuqua's Voting Profile

Registered to vote since: October 24, 2016

Party Affiliation: No known party affiliation

Status: A

Precinct: 09

District: 004

Polling place: Shelter Rock School Gym

Voter ID: 004716482

Congressional District: 005

House District: 109

Senate District: 024

Juan Antonio Fuqua Adress & Maps

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Thomas Gerard Adams

Neighbors for Juan Antonio Fuqua

1 Nicholas Street, Danbury, 06810-7108
No known party affiliation
2 Nicholas Street, Danbury, 06810-7109
No known party affiliation
2 Nicholas Street, Danbury, 06810-7109
No known party affiliation
3 Nicholas Street, Danbury, 06810-7108
No known party affiliation
4 Nicholas Street, Danbury, 06810-7109
No known party affiliation
4 Nicholas Street, Danbury, 06810-7109
No known party affiliation
5 Nicholas Street, Danbury, 06810-7108
No known party affiliation
6 Nicholas Street, Danbury, 06810-7109
No known party affiliation
6 Nicholas Street, Danbury, 06810-7109
No known party affiliation
6 Nicholas Street, Danbury, 06810-7109
No known party affiliation
6 Nicholas Street 6, Danbury, 06810-7109
No known party affiliation
7 Nicholas Street, Danbury, 06810-7108
No known party affiliation
7 Nicholas Street, Danbury, 06810-7108
No known party affiliation
8 Nicholas Street, Danbury, 06810-7109
No known party affiliation
8 Nicholas Street, Danbury, 06810-7109
No known party affiliation

Income

Salary: $21,875

Net Worth: $527,748

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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