Peter Olson

Male, Age 43 Ledyard, Connecticut

Peter Olson is a 43 years old male, born on Thursday, 26th of June 1980. He will turn 44 on June 26, 2025. Our records show he currently resides at 711 Shewville Road, Ledyard, Ct 06339-1443 and is affiliated with the No known party affiliation. Peter is registered to vote in Connecticut since June 19, 2012.

Overview of Peter Olson

Age: 43

Gender: male

Birth year: 1980

Lives in: Ledyard

Peter Olson's Voting Profile

Registered to vote since: June 19, 2012

Party Affiliation: No known party affiliation

Status: I

Precinct: 00

District: 001

Polling place: Gallup Hill School

Voter ID: 004212428

Congressional District: 002

House District: 042

Senate District: 019

Peter Olson Adress & Maps

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Thomas Gerard Adams

Neighbors for Peter Olson

693 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
694 Shewville Road, Ledyard, Ct 06339-1442
No known party affiliation
694 Shewville Road, Ledyard, Ct 06339-1442
No known party affiliation
695 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
695 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
699 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
699 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
715 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
715 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
715 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
715 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
719 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
719 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
723 Shewville Road, Ledyard, Ct 06339-1443
No known party affiliation
746 Shewville Road, Ledyard, Ct 06339-1324
No known party affiliation

Income

Salary: $103,728

Net Worth: $157,694

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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