Elvia Rivera

Female, Age 35 Danbury, Connecticut

Elvia Rivera is a 35 years old female, born on Sunday, 28th of June 1987. She will turn 36 on June 28, 2024. Our records show she currently resides at 2701 Eaton Court, Danbury, 06811-4066 and is affiliated with the No known party affiliation. Elvia is registered to vote in Connecticut since April 17, 2012.

Overview of Elvia Rivera

Age: 35

Gender: female

Birth year: 1987

Lives in: Danbury

Elvia Rivera's Voting Profile

Registered to vote since: April 17, 2012

Party Affiliation: No known party affiliation

Status: A

Precinct: 09

District: 003

Polling place: Stadley Rough School

Voter ID: 004198929

Congressional District: 005

House District: 109

Senate District: 024

Elvia Rivera Adress & Maps

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Mailing Address

Freedom Crossing Trail, Jacksonville, 32256 Fl

Thomas Gerard Adams

Neighbors for Elvia Rivera

2502 Eaton Court, Danbury, 06811-4065
No known party affiliation
2506 Eaton Court, Danbury, 06811-4065
No known party affiliation
2506 Eaton Court, Danbury, 06811-4065
No known party affiliation
2507 Eaton Court, Danbury, 06811-4065
No known party affiliation
2507 Eaton Court, Danbury, 06811-4065
No known party affiliation
2508 Eaton Court, Danbury, 06811-4065
No known party affiliation
2508 Eaton Court, Danbury, 06811-4065
No known party affiliation
2701 Eaton Court, Danbury, 06811-4066
No known party affiliation
2701 Eaton Court, Danbury, 06811-4066
No known party affiliation
2703 Eaton Court, Danbury, 06811-4066
No known party affiliation
2705 Eaton Court, Danbury, 06811-4066
No known party affiliation
2705 Eaton Court, Danbury, 06811-4066
No known party affiliation
2706 Eaton Court, Danbury, 06811-4066
No known party affiliation
2706 Eaton Court, Danbury, 06811-4066
No known party affiliation
2707 Eaton Court, Danbury, 06811-4066
No known party affiliation

Income

Salary: $63,808

Net Worth: $67,313

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.