Weldon E French

Male, Age 88 Lisbon , Connecticut

Weldon E French is a 88 years old male, born on Friday, 29th of November 1935. He will turn 89 on November 29, 2024. Our records show he currently resides at 3 Kenyon Road, Lisbon , Ct 06351-3014 and is not affiliated with any political party. Weldon is registered to vote in Connecticut since June 3, 2000.

Overview of Weldon E French

Age: 88

Gender: male

Birth year: 1936

Lives in: Lisbon

Phone number: 860-376-0882

Weldon E French's Voting Profile

Registered to vote since: June 3, 2000

Party Affiliation: No known party affiliation

Status: A

Precinct: 00

District: 002

Polling place: Lisbon Senior Center

Voter ID: 003116540

Congressional District: 002

House District: 047

Senate District: 019

Weldon E French Adress & Maps

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Thomas Gerard Adams

Neighbors for Weldon E French

9 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
9 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
9 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
10 Kenyon Road, Lisbon , Ct 06351-3013
No known party affiliation
10 Kenyon Road, Lisbon , Ct 06351-3013
No known party affiliation
13 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
13 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road Apt A, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation
15 Kenyon Road, Lisbon , Ct 06351-3014
No known party affiliation

Income

Salary: $31,804

Net Worth: $1,047,378

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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