Alexandra Allen

Female, Age 76 Danbury, Connecticut

Alexandra Allen is a 76 years old female, born on Wednesday, 26th of March 1947. She will turn 77 on March 26, 2024. Our records show she currently resides at 29 Birch Road, Danbury, Ct 06811-3422 and is affiliated with the No known party affiliation. Alexandra is registered to vote in Connecticut since January 1, 1800.

Overview of Alexandra Allen

Age: 76

Gender: female

Birth year: 1947

Lives in: Danbury

Phone number: 203-798-2161

Alexandra Allen's Voting Profile

Registered to vote since: January 1, 1800

Party Affiliation: No known party affiliation

Status: A

Precinct: 38

District: 001

Polling place: Danbury High School Gym

Voter ID: 002694158

Congressional District: 005

House District: 138

Senate District: 024

Alexandra Allen Adress & Maps

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Thomas Gerard Adams

Neighbors for Alexandra Allen

23 Birch Road, Danbury, Ct 06811-3422
No known party affiliation
24 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
26 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
27 Birch Road, Danbury, Ct 06811-3422
No known party affiliation
27 Birch Road, Danbury, Ct 06811-3422
No known party affiliation
28 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
28 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
30 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
30 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
31 Birch Road, Danbury, Ct 06811-3422
No known party affiliation
31 Birch Road, Danbury, Ct 06811-3422
No known party affiliation
32 Birch Road, Danbury, Ct 06811-0000
No known party affiliation
32 Birch Road, Danbury, Ct 06811-3456
No known party affiliation
33 Birch Road, Danbury, Ct 06811-3422
No known party affiliation
33 Birch Road, Danbury, Ct 06811-3422
No known party affiliation

Income

Salary: $67,182

Net Worth: $410,175

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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