Patricia L Strout

Female, Age 69 Danbury, Connecticut

Patricia L Strout is a 69 years old female, born on Thursday, 2nd of April 1953. She will turn 70 on April 02, 2024. Our records show she currently resides at 163 South Street 6, Danbury, 06810-7923 and is not affiliated with any political party. Patricia is registered to vote in Connecticut since January 1, 1800.

Overview of Patricia L Strout

Age: 69

Gender: female

Birth year: 1953

Lives in: Danbury

Patricia L Strout's Voting Profile

Registered to vote since: January 1, 1800

Party Affiliation: No known party affiliation

Status: A

Precinct: 10

District: 005

Polling place: War Memorial Gym

Voter ID: 002684630

Congressional District: 005

House District: 110

Senate District: 024

Patricia L Strout Adress & Maps

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Thomas Gerard Adams

Neighbors for Patricia L Strout

136 South Street, Danbury, 06810-8041
No known party affiliation
136 South Street 2, Danbury, 06810-8041
No known party affiliation
156 South Street, Danbury, 06810-7951
No known party affiliation
157 South Street B1, Danbury, 06810-7950
No known party affiliation
157 South Street B1, Danbury, 06810-7950
No known party affiliation
160 South Street, Danbury, 06810-7951
No known party affiliation
161 South Street, Danbury, 06810-7950
No known party affiliation
163 South Street 31, Danbury, 06810-7923
No known party affiliation
163 South Street 52, Danbury, 06810-7923
No known party affiliation
163 South Street 83, Danbury, 06810-7923
No known party affiliation
163 South Street 85, Danbury, 06810-7923
No known party affiliation
163 South Street 70, Danbury, 06810-7923
No known party affiliation
163 South Street 93, Danbury, 06810-7923
No known party affiliation
163 South Street 50, Danbury, 06810-7923
No known party affiliation
163 South Street 59, Danbury, 06810-7923
No known party affiliation

Income

Salary: $37,575

Net Worth: $1,317,967

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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