Louann Marks

Female, Age 64 Danbury, Connecticut

Louann Marks is a 64 years old female, born on Friday, 18th of October 1957. She will turn 65 on October 18, 2025. Our records show she currently resides at 9799 Park Avenue 83, Danbury, 06810-7604 and is not affiliated with any political party. Louann is registered to vote in Connecticut since January 1, 1800.

Overview of Louann Marks

Age: 64

Gender: female

Birth year: 1958

Lives in: Danbury

Phone number: 203-730-2121

Louann Marks's Voting Profile

Registered to vote since: January 1, 1800

Party Affiliation: No known party affiliation

Status: A

Precinct: 10

District: 006

Polling place: Park Avenue School Gym

Voter ID: 002684079

Congressional District: 005

House District: 110

Senate District: 024

Louann Marks Adress & Maps

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Thomas Gerard Adams

Neighbors for Louann Marks

115 Park Avenue 14, Danbury, 06810-7556
No known party affiliation
115 Park Avenue 14, Danbury, 06810-7556
No known party affiliation
115 Park Avenue 15, Danbury, 06810-7556
No known party affiliation
117 Park Avenue, Danbury, 06810-7504
No known party affiliation
121 Park Avenue 1, Danbury, 06810-7559
No known party affiliation
1175 Park Avenue, Danbury, 06810-0000
No known party affiliation
1175 Park Avenue, Danbury, 06810-0000
No known party affiliation
9799 Park Avenue 10, Danbury, 06810-7604
No known party affiliation
9799 Park Avenue 50, Danbury, 06810-7604
No known party affiliation
9799 Park Avenue 12, Danbury, 06810-7604
No known party affiliation
9799 Park Avenue 86, Danbury, 06810-7604
No known party affiliation
9799 Park Avenue 86, Danbury, 06810-7604
No known party affiliation
9799 Park Avenue 31, Danbury, 06810-7604
No known party affiliation
11712 Park Avenue, Danbury, 06810-7504
No known party affiliation
11712 Park Avenue, Danbury, 06810-7504
No known party affiliation

Income

Salary: $80,759

Net Worth: $906,775

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.