Rose M Ross

Female, Age 93 Danbury, Connecticut

Rose M Ross is a 93 years old female, born on Thursday, 13th of February 1930. She will turn 94 on February 13, 2024. Our records show she currently resides at 18 Berkshire Drive, Danbury, Ct 06811-4714 and is affiliated with the No known party affiliation. Rose is registered to vote in Connecticut since January 1, 1800.

Overview of Rose M Ross

Age: 93

Gender: female

Birth year: 1931

Lives in: Danbury

Rose M Ross's Voting Profile

Registered to vote since: January 1, 1800

Party Affiliation: No known party affiliation

Status: A

Precinct: 38

District: 001

Polling place: Danbury High School Gym

Voter ID: 002673418

Congressional District: 005

House District: 138

Senate District: 024

Rose M Ross Adress & Maps

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Thomas Gerard Adams

Neighbors for Rose M Ross

13 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
13 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
13 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
15 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
16 Berkshire Drive, Danbury, Ct 06811-0000
No known party affiliation
17 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
17 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
19 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
19 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
20 Berkshire Drive, Danbury, Ct 06811-4714
No known party affiliation
20 Berkshire Drive, Danbury, Ct 06811-4714
No known party affiliation
21 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
21 Berkshire Drive, Danbury, Ct 06811-4713
No known party affiliation
22 Berkshire Drive, Danbury, Ct 06811-4714
No known party affiliation
22 Berkshire Drive, Danbury, Ct 06811-0000
No known party affiliation

Income

Salary: $17,634

Net Worth: $1,006,927

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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