Marcia A Bradley

Female, Age 68 Old Saybrook, Connecticut

Marcia A Bradley is a 68 years old female, born on Sunday, 26th of June 1955. She will turn 69 on June 26, 2024. Our records show she currently resides at 14 Dogwood Lane, Old Saybrook, Ct 06475-2011 and is affiliated with the No known party affiliation. Marcia is registered to vote in Connecticut since October 18, 1988. Our records show Richard D Bradley (68) and Kelly L Bradley (35) as possible relatives.

Overview of Marcia A Bradley

Age: 68

Gender: female

Birth year: 1956

Lives in: Old Saybrook

Phone number: 860-388-4829

Marcia A Bradley's Voting Profile

Registered to vote since: October 18, 1988

Party Affiliation: No known party affiliation

Status: A

Precinct: 00

District: 002

Polling place: Old Saybrook High School Gymnasium

Voter ID: 000478151

Congressional District: 002

House District: 023

Senate District: 033

Marcia A Bradley Adress & Maps

Show Map

Thomas Gerard Adams

Neighbors for Marcia A Bradley

8 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
9 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
10 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
10 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
10 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
10 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
12 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation
14 Dogwood Lane, Old Saybrook, Ct 06475-2011
No known party affiliation

Related Persons

Marcia A Bradley's parents, siblings, grandparents, aunts, uncles, cousins, and other extended family members.

Old Saybrook, Ct
Born on: Monday, 3rd of October 1955
Gender: Male
Old Saybrook, Ct
Born on: Friday, 19th of August 1988
Gender: Female

Income

Salary: $36,423

Net Worth: $808,257

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.