Alan R Tokay

Male, Age 72 Bristol, Connecticut

Alan R Tokay is a 72 years old male, born on Tuesday, 18th of October 1949. He will turn 73 on October 18, 2024. Our records show he currently resides at 137 Rhoda Lane, Bristol, 06010-9009 and is affiliated with the No known party affiliation. Alan is registered to vote in Connecticut since October 19, 1992.

Overview of Alan R Tokay

Age: 72

Gender: male

Birth year: 1950

Lives in: Bristol

Phone number 860-582-7129

Alan R Tokay's Voting Profile

Registered to vote since: October 19, 1992

Party Affiliation: No known party affiliation

Status: A

Precinct: 01

District: 077

Polling place: Edgewood School

Voter ID: 002790568

Congressional District: 001

House District: 077

Senate District: 031

Alan R Tokay Adress & Maps

Residential Address

137 Rhoda Lane, Bristol, 06010-9009

Thomas Gerard Adams

Neighbors for Alan R Tokay

133 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
134 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
134 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
135 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
135 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
136 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
136 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
137 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
142 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
143 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
145 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
145 Rhoda Lane, Bristol, 06010-9009
No known party affiliation
146 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
146 Rhoda Lane, Bristol, 06010-9010
No known party affiliation
147 Rhoda Lane, Bristol, 06010-9009
No known party affiliation

Income

Salary: $110,473

Net Worth: $797,915

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.