John M Spigel

Male, Age 75 Ledyard, Connecticut

John M Spigel is a 75 years old male, born on Monday, 10th of May 1948. He will turn 76 on May 10, 2024. Our records show he currently resides at 226 Lambtown Road, Ledyard, Ct 06339-1928 and is affiliated with the No known party affiliation. John is registered to vote in Connecticut since September 21, 1984. Our records show Nancy Spigel (75) as possible relative.

Overview of John M Spigel

Age: 75

Gender: male

Birth year: 1948

Lives in: Ledyard

Phone number 860-572-9787

John M Spigel's Voting Profile

Registered to vote since: September 21, 1984

Party Affiliation: No known party affiliation

Status: A

Precinct: 00

District: 001

Polling place: Gallup Hill School

Voter ID: 001200127

Congressional District: 002

House District: 042

Senate District: 019

John M Spigel Adress & Maps

Residential Address

226 Lambtown Road, Ledyard, Ct 06339-1928

Thomas Gerard Adams

Neighbors for John M Spigel

224 Lambtown Road, Ledyard, Ct 06339-1928
No known party affiliation
224 Lambtown Road, Ledyard, Ct 06339-1928
No known party affiliation
225 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
225 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
225 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
225 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
225 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
231 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
231 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation
231 Lambtown Road, Ledyard, Ct 06339-1929
No known party affiliation

Related Persons

John M Spigel's parents, siblings, grandparents, aunts, uncles, cousins, and other extended family members.

Ledyard, Ct
Born on: Sunday, 1st of February 1948
Gender: Female

Income

Salary: $48,256

Net Worth: $1,031,885

*This information is estimated by an algorithm and does not come from any public data. These numbers are only guesses and should not be considered to be accurate.

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